Imaginary numbers: polar form division: switching of signs

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Recently I have started studying imaginary numbers. I've come at the division of complex numbers in polar form. However when I do the exercise I get almost exactly the same answer as in my textbook except in the textbook they switch the signs for reasons I don't quite understand.

The following image is the example from the textbook image

division of z1 and z2

$$ z_1= \frac12 \cos⁡(3\pi / 4)+ i \sin⁡(3\pi/4) $$ $$ z_2 =4 \cos⁡(11\pi / 6)+ i \sin⁡(11π/6) $$

At the last step of the example the signs are switched but I don't understand why. Why do they do that?

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The first $-$ signs come from actually computing the differences. Then use the fact that $\cos$ is an even function, i.e. $\cos(-x)=\cos(x),$ and $\sin$ is odd, i.e. $\sin(-x) = -\sin x.$