I have been trying to implicitly differentiate $$y = 2vx\cos (x^2)$$, where y, v and x are variables. All I need to know is how to differentiate$$ 2vx\cos(x^2)$$ implicitly.
What I am thinking if is that, by using product rule I will need to differentiate v once, then$ x$ once and then$\ cos(x^2)$ once. Is this the right approach ?
$$y = 2vx\cos (x^2)$$ is a product of three function so you have to apply product rule carefully.
Note that if you have $$y=f(x)g(x)h(x)$$ then $$y'= f'(x)g(x)h(x)+ f(x)g'(x)h(x)+f(x)g(x)h'(x)$$
You should be able to take over from here.