Improper integral with derivative within integral

39 Views Asked by At

What is the value of $\displaystyle \int_{-\infty}^\infty f(x)f''(x)\,dx$ where $f(x)=\dfrac{\alpha}{(x^2+\beta^2)},\quad \alpha,\beta \in \mathbb{R}$? I have tried to use the Fourier transform of $f(x)$ which is an exponential function, but stuck somewhere?

1

There are 1 best solutions below

0
On BEST ANSWER

Integrating by parts we have $\int_{-\infty} ^{\infty} f(x)f''(x)dx=-\int_{-\infty} ^{\infty} (f'(x))^{2}dx $ $= -\int_{-\infty} ^{\infty}\frac {(2\alpha x)^{2}} {(x^{2}+\beta^{2})^{2}}$ dx. You can easily evaluate this bu the substitution $x=\beta \tan(\theta)$.