Find the value of
$$\int_0^1(x \ln x)^3dx $$
Taking a substitute $x=e^{-y}$ i get the value as $$-3\over128$$
Does it look good ?
2026-05-14 15:57:17.1778774237
Improper Integrals Problem
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Mathematica returns your answer too:
In:= Integrate[(x Log[x])^3,{x,0,1}]Out=-3/128