I tried it this way... $(ab)^{n}=o$ then $a(ba)^{n-1}b=0$ but then we can't conclude anything from this as a and b may not have inverses..
Thanks for any help!!
I tried it this way... $(ab)^{n}=o$ then $a(ba)^{n-1}b=0$ but then we can't conclude anything from this as a and b may not have inverses..
Thanks for any help!!
Try it the other way around: If $(ab)^n = 0$ then $b(ab)^na = 0$.