Chebyshev DE: $$(1-x^2)y''-xy'+n^2y=0$$
The general solution for the DE is: $$y(t)=C\cos(nt+\alpha)$$
I found that books sets the constants to be: ${C=1, \alpha=0}$
Why we set these values ?
Thanks in advance
2026-03-26 17:30:14.1774546214
In Chebyshev general solution, why the constants are set to ${0,1}$?
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