In how many ways can $16$ executives, including two brothers, be arranged around a circular table if the two brothers can't be seated together?

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There are $16$ executives, including two brothers. In how many ways can they be arranged around a circular table if the two brothers can't be seated together?

I tried putting each of the brothers in between the $14$ executives by $13! \cdot 14C2 \cdot 2$.

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This can be easily calculated by substracting the number of ways in which they sit together from the total number of ways