Integrate :- $\displaystyle\int\dfrac{2x^2}{2x\cos(2x)+(x^2-1)\sin(2x)}$
I tried dividing by $\cos^2(x)$ and then substituting $\tan(x)=t$.
Integrate :- $\displaystyle\int\dfrac{2x^2}{2x\cos(2x)+(x^2-1)\sin(2x)}$
I tried dividing by $\cos^2(x)$ and then substituting $\tan(x)=t$.
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