How to integrate $$\frac{\sec^2 x}{({\sec x+\tan x})^{9/2}}$$ with respect to $x$. I tried to express the denominator in the form of half angles but i could not succeed
2026-04-29 17:16:48.1777483008
Indefinite Integration with trigonometric functions
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Big Hint:
Use the substitution $u=\sec x+\tan x$, and notice that $\frac{1+u^2}{2u}=\sec x$.