Induction $n! - n^4 \ge n^2 - 11n\,$ for $\,n \ge \text{some } n_0$.

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Task is to show that

There exists some $n_{0} \in \mathbb N $, $\forall n \in \mathbb N $

$ (n_{0} \ge n \Rightarrow n! - n^4 \ge n^2 - 11n)$

Where to start with this?

By Induction over $n$, assuming $n_{0} =1:$

Holds for $n_{0} =1:$

Assume $ k! - k^4 \ge k^2 - 11k $

Show: $ (k+1)! - (k+1)^4 = ....$

Do not want the answer just headsup on the approach.. Thanks.