Is the following true for $\|x\|,\|y\|\geq 1$ and $x,y\in X$, where $X$ is a normed space
$$\left\| \frac{x}{\|x\|} + \frac{y}{\|y\|} \right\| \leq \| x+y\|.$$
Is the following true for $\|x\|,\|y\|\geq 1$ and $x,y\in X$, where $X$ is a normed space
$$\left\| \frac{x}{\|x\|} + \frac{y}{\|y\|} \right\| \leq \| x+y\|.$$
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NO. Let $X=\mathbb R^2.$ Let $\|(u,v)\|=\max (|u|,|v|).$ Let $x=(1,1)$ and $y=(-1/2,-3/2).$ So $\|x\|=1$ and $\|y\|=3/2.$ We have $\frac {x}{\|x\|}=x$ and $\frac {y}{\|y\|}\|=(-1/3,-1).$ So $$\|\frac {x}{\|x\|}+\frac {y}{\|y\|}\|=\|(1,1)+(-1/3,-1)\|=\|(2/3,0)\|=2/3$$ which is greater than$$\|x+y\|=\|(1,1)+(-1/2,-3/2)\|=\|(-1/2,-1/2)\|=1/2.$$