Since $1^\infty$ results in indetermination ,does $2^\infty$ result in the same?
(I think I'm basically asking if $b^\infty$, with $b \in \mathbb{R} $, results in indetermination)
And why is the result of a limit in the form $1^\infty$ an indetermination?
Thank you!
$$2^{+\infty}=e^{+\infty\ln (2)}=$$ $$=e^{+\infty}=+\infty $$
It is not indeterminate.
It is $+\infty $ because $\ln (2)>0$.