How can I prove that
$$\sum_{n=1}^{\infty}\frac{H_n}{q^n}=\frac{q}{q-1}\log(\frac{q}{q-1})$$
($H_n=\sum_{k=1}^n\frac{1}{k}$, $|q|>1$).
How can I prove that
$$\sum_{n=1}^{\infty}\frac{H_n}{q^n}=\frac{q}{q-1}\log(\frac{q}{q-1})$$
($H_n=\sum_{k=1}^n\frac{1}{k}$, $|q|>1$).
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