Infinite Series $\sum\limits_{n=1}^\infty\frac{H_n}{q^n}$

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How can I prove that

$$\sum_{n=1}^{\infty}\frac{H_n}{q^n}=\frac{q}{q-1}\log(\frac{q}{q-1})$$

($H_n=\sum_{k=1}^n\frac{1}{k}$, $|q|>1$).

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Hints:

  1. Look at the partial sums of $\sum_{n=1}^{\infty}\frac{H_n}{q^n}$ as fractions.
  2. Your equation fail if $|q| > 1$ is false.