Does the integral $\int_{K} (z+1)\log (z+1) dz$, where $ K=\partial D(0,3)$, exist? If the answer is yes, what is it's value? I see that $f(z)=(z+1)\log (z+1)$ is not continuous at the point $-3$ and we know by definition of curve integral that $f$ must be continuous on the Image of the curve. Any help please?
2026-04-08 05:38:50.1775626730
$\int_{K} (z+1)\log (z+1) dz$, where $ K=\partial D(0,3)$, exist?
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