Given the general equation of an hyperbola
$Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0 $ where $B^2-4AC>0$
is it possible to find all integers solutions $(x,y)$ as a function of $A, B, C, D$ and $ F $ ? Eventually all the coefficient can be integers as well.
In particular i'm looking for the integer solutions of the equation $2x^2-y^2-y=0$
Thanks
Your final equation turns into $(2y+1)^2 - 8 x^2 = 1.$ In the output below, we show how to get all $U_n^2 - 8 V_n^2 = 1,$ where we get $$ U_{n+2} = 6 U_{n+1} - U_n, $$ $$ V_{n+2} = 6 V_{n+1} - V_n. $$ So, let's see, for you, $x_n = V_n.$ Note that $U_n$ is always odd, and $y_n = \frac{U_n - 1}{2}.$ If you want to include the negative values of $y,$ take $2y+1 = -U$ or $y_n' = \frac{-U_n - 1}{2}.$