Tried multiplying and dividing my $x^4$ and also tried substitutions for $x^{1/2}$ , $x^{1/4}$ but reaching nowhere , just give me the clue on how to start .
2026-04-18 02:53:43.1776480823
Integral $\frac{x^{1/4} }{ x^{1/2}-1}$ dx
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A start: Let $x=u^4$. Then we end up wanting to integrate $\frac{4u^4}{u^2-1}$. Note this is $\frac{4(u^4-1)}{u^2-1}+\frac{4}{u^2-1}$. Continue.