Integral of exponential

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I have the expected value of the square of the position operator given as

$$\langle x^{2} \rangle= \int_{-\infty}^{\infty} x^{2}e^{\frac{amx^{2}}{h}}dx$$

I understand that the integrand can only be evaluated by the form $$ \int_{-\infty}^{\infty} x^{2} e^{-ax^{2}}dx=\frac{1}{2}\sqrt{\frac{\pi}{a^{3}}}$$

but it does not yield the correct answer to my solution sheet.

Where am I going wrong?