Solve: $$\int\frac{1}{4x^2+4x+2}dx$$
I think it may related to $\tan^{-1}x$. Any hint?
Hint: The denominator turns into $$(2x+1)^2+1$$
so you can make the substitution $$y = 2x+1$$ to turn the integral into
$$\frac{1}{2}\int \frac{1}{y^2+1}\ dy$$
Then try to make a trigonometric substitution.
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Hint: The denominator turns into $$(2x+1)^2+1$$
so you can make the substitution $$y = 2x+1$$ to turn the integral into
$$\frac{1}{2}\int \frac{1}{y^2+1}\ dy$$
Then try to make a trigonometric substitution.