Integral of $\int \frac{1}{x^2(x^4+1)^{3/2}}dx$

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How to find

$$\int \frac{1}{x^2(x^4+1)^{3/2}}dx$$

I tried taking $x^4$ common but that generated $x^8$ outside which made things complicated. Putting $x^4+1=t^2$ also didn't solve the query. Can someone hint something?