Evaluating the following improper integral using WolframAlpha gives complex value:
$$\int_{-\infty}^{\infty}\frac{\sqrt[3]{x}}{1+x^2}dx=\sqrt[6]{-1}\pi\approx2.7+i1.5$$
Stating that the function is odd then the limit of the integral is zero, why does WolframAlpha fail to evaluate infinite integrals of odd functions?