Consider the region bounded by these two lines in the first quadrant.
y=x+1 and y=3-x
Set-Up the integral for the volume of the solid obtained by revolving the region around the lines
y = -1 and x = -1
2026-04-07 19:36:20.1775590580
Integral revolving around $y=-1$ & $x=-1$
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You need to start by understanding what the region looks like, in detail. As you say, it looks like an upside-down V. Where is the point of the V? It's at the point where the two lines $y=x+1$ and $y=3-x$ intersect; what is that point? Where is the left edge of the region of integration? The right edge? You will need all of that information to set up the integral for the volume of the solid of revolution.
Also, it's not clear from your original post what the line about which you are revolving is.