How do I integrate $$\int{\frac{1}{x\sqrt{1-x^3}}dx}$$
Not able to think of a method. Any hint is appreciated. Thanks
Hint:
Generalization:
$$\dfrac1{x\sqrt[n]{1-x^m}}=\dfrac{mx^{m-1}}{mx^m\sqrt[n]{1-x^m}}$$
Now choose $\sqrt[n]{1-x^m}=v\implies dv=?$
Hint : Substitute $u=\sqrt{1-x^3}$
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Hint:
Generalization:
$$\dfrac1{x\sqrt[n]{1-x^m}}=\dfrac{mx^{m-1}}{mx^m\sqrt[n]{1-x^m}}$$
Now choose $\sqrt[n]{1-x^m}=v\implies dv=?$