$$\int \frac1{ \cos(x-a)\cos(x-b)} \, \mathrm{d}x$$ Can someone help me to integrate this function by method of substitution.I am not able to start it for possibilities are not coming in my mind. If different substitutions are available please let me know?
2026-04-13 17:25:38.1776101138
Integrate the function by substitution method.
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Multiply top an bottom by $\sin(b-a)$ and then write $$\sin(b-a)=\sin[(x-a)-(x-b)]=\sin(x-a)\cos(x-b)-\sin(x-b)\cos(x-a).$$