what would be the integrating factor for:
$$\frac{dy}{dx}-4y=e^{4x}\cosh^23x$$
Would it be $4x$? Thank You.
No, it would not be $4x$.
If you have a differential equation in the form
$$\frac{dy}{dx} +p(x)y = q(x)$$
the integrating factor is $I(x) = \exp(\int p(x)dx)$. In your case, $p(x) = -4$ so $I(x) = \exp(\int -4 dx)$. Can you take it from here?
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No, it would not be $4x$.
If you have a differential equation in the form
$$\frac{dy}{dx} +p(x)y = q(x)$$
the integrating factor is $I(x) = \exp(\int p(x)dx)$. In your case, $p(x) = -4$ so $I(x) = \exp(\int -4 dx)$. Can you take it from here?