I am given the following indefinite integral:
$\int x\sqrt{1+2x}~dx$ using the substitution $u=\sqrt{1+2x}$
I am not sure where to begin, I know that $du=\dfrac{1}{\sqrt{1+2x}}$
But how can I get this integral in terms of $u$ when there is a $x$ in front?
Any help would be appreciated.
Thanks.
Hint : Use $x=\frac{u^2-1}{2}$ to get dx = u du