I wanted to know is this true for an even function $\mathbf f(x)$:
$\int_a^b$$\mathbf f(x)$ $\mathbf =$$\int_b^a$$\mathbf f(x)$
That is, there is no requirement of a negative sign while interchanging the limits of integration.
I wanted to know is this true for an even function $\mathbf f(x)$:
$\int_a^b$$\mathbf f(x)$ $\mathbf =$$\int_b^a$$\mathbf f(x)$
That is, there is no requirement of a negative sign while interchanging the limits of integration.
No, it is not true, since, by definition, if $b<a$, then $\displaystyle\int_b^af(x)\,\mathrm dx=-\int_a^bf(x)\,\mathrm dx$.