Here's the problem
And immediately after is the solution, with no intermediate steps
What steps occurred in order to obtain the inequality after $Note$?
It is known that for all $x$, $\sin (\frac{1}{x})^2 \le 1$
This implies that $-1\le \sin(\frac{1}{x}) \le 1$ was used.
In general,$-|t| \le t\sin(\frac{1}{x}) \le |t|$.
In this case, $t=\sqrt [ 5 ]{x } $
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It is known that for all $x$, $\sin (\frac{1}{x})^2 \le 1$
This implies that $-1\le \sin(\frac{1}{x}) \le 1$ was used.
In general,$-|t| \le t\sin(\frac{1}{x}) \le |t|$.
In this case, $t=\sqrt [ 5 ]{x } $