How can we prove -
$$|\dot{u}(x) - \tilde{u_h}(x)| \leqslant h \left[\max_{0 \leqslant y\leqslant1}\ddot{u}(y)\right],$$
where $0\leqslant x\leqslant 1$ and $\tilde{u_h}$ is interpolant of $u$.
How can we prove -
$$|\dot{u}(x) - \tilde{u_h}(x)| \leqslant h \left[\max_{0 \leqslant y\leqslant1}\ddot{u}(y)\right],$$
where $0\leqslant x\leqslant 1$ and $\tilde{u_h}$ is interpolant of $u$.
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