Let's consider the following IVP:
$y'' + 2y' + 10 y = \delta(t)$
$y(0) = y'(0) = 0$
where $\delta$ is the Dirac delta function. If I solve the IVP using the Laplace transform, I get $y(t) = \frac{1}{3} e^{-t} \sin 3 t $. However, this function does not satisfy the initial conditions, as $y'(0) = 1$.
How would you interpret this result?