I obtained the group $G$ which is the semidirect product $(\mathbb{Z}_5 \times \mathbb{Z}_5) \rtimes \mathbb{Z}_3$ in GAP as below.
gap> m:=[[4,0],[0,2]]*One(GF(5));
[ [ Z(5)^2, 0*Z(5) ], [ 0*Z(5), Z(5) ] ]
gap> s1:=SemidirectProduct(Group(m),GF(5)^2);
<matrix group of size 100 with 3 generators>
And when I obtained the elements of $G$ I get a list which continues as follows.
gap> Elements(s1);
[ [ [ Z(5)^0, 0*Z(5), 0*Z(5) ], [ 0*Z(5), Z(5)^0, 0*Z(5) ], [ 0*Z(5), 0*Z(5), Z(5)^0 ] ],
[ [ Z(5)^0, 0*Z(5), 0*Z(5) ], [ 0*Z(5), Z(5)^0, 0*Z(5) ], [ 0*Z(5), Z(5)^0, Z(5)^0 ] ],
[ [ Z(5)^0, 0*Z(5), 0*Z(5) ], [ 0*Z(5), Z(5)^0, 0*Z(5) ], [ 0*Z(5), Z(5), Z(5)^0 ] ],
[ [ Z(5)^0, 0*Z(5), 0*Z(5) ], [ 0*Z(5), Z(5)^0, 0*Z(5) ], [ 0*Z(5), Z(5)^2, Z(5)^0 ] ],...
I want to write the elements as $(\bar0,(\bar0,\bar0)),(\bar0,(\bar0,\bar1)),(\bar0,(\bar0,\bar2))$,....
Can someone please tell how to interpret the elements in the above list which are present as [ Z(5)^0, 0*Z(5), 0*Z(5) ], [ 0*Z(5), Z(5)^0, 0*Z(5) ] ... to obtain the form I want.
What does Z(5)^0, 0*Z(5) mean?
Thanks a lot in advance.
The notation
Z(5)stands for a generator of the unit group of the finite field with five elements. SoZ(5)^0is $1$, and0*Z(5)is $0$ is the finite field. The commandIntFFEwill convert these numbers for you.