I have seen the question that is similar but I do not understand the answer whatsoever.
I have a group ring $R:=\mathbb{Q}S_3$ and want to find inverse of
$x=e+(2\,3) -(1\,3\,2)$
So is my $x^{-1}$ of the form
$e+ (a \, b)+(a\,c)+(b\,c)+(a\,b\,c)+(a\,c\,b)$
Or? And if so, how on earth do I solve using $xx^{-1}=e$?