In this problem, I multiplied the left side of the AX=B equation by the inverse of A, but what I am confused about is why then I must multiply B by the inverse of A in this order: (inverse of A) * (B). When I do (B) * (inverse of A), it is wrong, but why?
2026-04-25 11:40:33.1777117233
Inverse Matrix Multiplication Problem
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2

We have that
$$AX=B$$
and by left multiplication by $A^{-1}$ and associativity we obtain
$$A^{-1}(AX)=A^{-1}B\implies (A^{-1}A)X=A^{-1}B\implies X=A^{-1}B$$
Recall also that matrix multiplication is not commutative and moreover in that case the multiplication $BA^{-1}$ is not well defined since the dimensions of the two matrices, for a multiplication in that order, are not compatible.