Is $\{ 0 \}$ a basis of the free module $\{ 0 \}$?

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I'm studying modules by reading Dummit and Foote, and I'm having a problem understanding the definition of a free module. I read this stackexchange question, but I couldn't figure it out.

The textbook defines a free module as following:

definition of a free module

The following is the example that I'm confused about.

Let $F = \{ 0 \}$. Then $F$ is a $\mathbb{Z}$-module since $F$ is an abelian group under addition.

In the stackexchange question, the empty set is given as the basis for $F$. That makes sense because $F$ has no nonzero elements, so it satisfies the definition vacuously.

But, using the same logic, wouldn't $F$ be a free $\mathbb{Z}$-module on the set $\{ 0 \}$?

I think that would be a problem because if that was the case, the rank of $\{ 0 \}$ would be both 0 and 1.

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The set $\{0\}$ is not linearly independent, because $r0=0$ for any nonzero $r\neq 0$.

The empty set does span the zero module, because an empty sum is zero.