Is any algebraic number a root of a given orthogonal polynomial?

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Let $S=\left\{P_n(x)\right\}_{n=0}^{\infty}$ be any sequence of $n$-degree polynomials which are orthogonal in the interval $(a,b)\in\mathbb{R}$. If $\xi$ is an arbitrary algebraic number such that $a<\xi<b$, then, is true that we can always find a finite positive integer $m$ such that $P_m(\xi)=0$?