Is $\Big| \frac{\zeta(1/2 + ix)}{\zeta(1/2 - ix)} \Big| \equiv 1$ for all $x \in \mathbb R$?

83 Views Asked by At

Suppose analytic continuation of the Riemann zeta function $\zeta(z)$, defined for all $z \in \mathbb C$, and let $x \in \mathbb R$.

Then, $\Big| \frac{\zeta(1/2 + ix)}{\zeta(1/2 - ix)}\Big| \equiv 1$? How would one show this identity?

1

There are 1 best solutions below

0
On BEST ANSWER

The $\zeta$ function is real for real parameters, hence $$ \forall w\in\mathbb{C},\qquad \zeta(\overline{w}) = \overline{\zeta(w)} $$ implying the statement, follows from Schwarz reflection principle.