Is the Baumslag-Solitar group $BS(1, 2)$ a knot group ($\pi_1$ of a knot complement in $\mathbb{R}^3$)?
It has the presentation $\langle a, b\hspace{1mm}| \hspace{1mm}aba^{-1} = b^2\rangle $.
Is the Baumslag-Solitar group $BS(1, 2)$ a knot group ($\pi_1$ of a knot complement in $\mathbb{R}^3$)?
It has the presentation $\langle a, b\hspace{1mm}| \hspace{1mm}aba^{-1} = b^2\rangle $.
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