I saw a post somewhere that stated that "each point in the Cantor set is the endpoint of some closed interval of the form $\big[\frac{n}{3^k}, \frac{n+1}{3^k}\big]$, with $n, k \in \mathbb{N}$, so each point in the Cantor set is rational." Is that true?
2026-03-27 04:16:39.1774584999
Is every point in the Cantor set rational?
767 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
No: the middle-thirds Cantor set is uncountable, while the set of rational numbers is countable. Therefore not every point in the Cantor set is rational.
It turns out that the elements of the Cantor set are precisely the real numbers in $[0,1]$ which have a ternary expansion consisting only of $0$s and $2$s. Note that this includes many points besides the endpoints of the intervals removed.