This is a very dumb question, but is $\mathrm{GL}(2,\mathbb{Z})$ is lie group? I don't think it is, since its underlying set don't form a manifold, but I am just not sure.
2026-04-24 19:56:20.1777060580
Is GL($2$,$\mathbb{Z}$) is lie group?
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Any group with at most countably many elements and the discrete topology is a zero-dimensional Lie group. So yes.