Is $\inf$ of a differentiable function still differentiable?

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Let's get to the point. Suppose we have a function $I(x,y) \in \mathbb{R}$, $I(x,y) \geq 0$, convex, and differentiable for $x \in X$ compact subset of $\mathbb{R}$, and $y \in \mathbb{R}$. Is

$$I(\omega) := \inf_{x \in X \\ {y = \omega x}} I(x,y) ,$$

$\omega \in \mathbb{R}$, still differentiable? Please, note that the function defined as $\tilde{I}(x,\omega) := I(x,\omega x)$ in general is not convex anymore.