Suppose I am selling boxes of cereal.
Each box has $m$ grams of cereal and costs $p$ pounds.
Two possible promotions:
- Decrease the price of the box by $20$%
- Put $20$% more cereal in each box.
Which offer would be better value for money?
My attempt:
Value for money is usually $v = \frac{m}{p}$ grams per pound.
In scenario 1:
Value for money changes to $\frac{m}{0.8p} = 1.25v$
In scenario 2:
Value for money changes to $\frac{1.2m}{p} = 1.2v$
So scenario 1 is better value for money?
Is my answer correct?
The reason I am unsure is that it doesn't seem 'obvious' to me that why reducing the price is better than increasing the size of the box. Since I am applying a $20$% promotion in both cases, I would have thought that both promotions are the same value for money but the maths doesn't say that.
Is this outcome 'obvious' to anyone?
In your two scenarios, you have
Case $1$ (decrease price): $v=\frac{m}{p}\cdot\frac{1}{0.8}$
Case $2$ (increase quantity): $v=\frac{m}{p}\cdot\frac{1.2}{1}$
So it comes down to which of $\frac{1}{0.8}$ or $\frac{1.2}{1}$ is bigger. Evidently $\frac{1}{0.8}$ is the winner.
In the general case, we take $0<x<1$ and compare $\frac{1}{1-x}$ and $\frac{1+x}{1}$.
We can cross multiply to compare. We can see $1>1-x^2$, which indicates that $\frac{1}{1-x}$ is the greater of the two fractions.