Suppose we have a family of sets $A_i \subset R$. Is it true that $\sum(A_i)=(\cup A_i)$. Brackets means ideal generation.
2026-04-02 15:39:57.1775144397
Is it true that summation of ideals equal to ideal generated by their generator
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Letting $a \in A_i$ for some $i$, is $a \in \sum(A_i)$? Letting $a_1 + a_2 + \dots + a_n \in \sum (A_i)$. Is $a_1 + a_2 + \dots + a_n \in (\cup A_i)$? Why is this sufficient to argue that your claim is true?