Is $M_n(R)$ Dedekind if $R$ is Dedekind?

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Definition: A ring is Dedekind if every nonzero proper ideal factors into a product of prime ideals.

Let $R$ be a ring. $M_n(R)$ denotes the ring of matrices with elements from $R$. Is $M_n(R)$ Dedekind if $R$ is Dedekind?

I think the answer should be in some textbook, but I can't find it.

PS: I don't care the order of factors, so communitivity is not concerned.

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If you are just referring to Dedekind domains, then of course $M_n(R)$ is never a domain for$n>1$. But the other important property (that $R$ is a hereditary ring) passes to $M_n(R)$.

Faith defined a Dedekind prime ring to be a hereditary, Noetherian, prime ring with no nontrivial idempotent ideals, and all those properties pass to the matrix ring, too. So the answer would be “yes” in that case.