I know that my question seems to be obvious, but I really need the answer
Let $\mathbb{Z}[x, y, z]$ be a polynomial ring. I know that it is a $\mathbb{Z}$-graded ring, but is it not in fact $\mathbb{N}$-graded? I don't see why it is not $\mathbb{N}$-graded if we consider the degrees of polynomials. But when I tried to use Nakayama's Lemma (the graded version), my professor told me that we cannot use it for any polynomial ring with coefficients in $\mathbb{Z}$.
Any help?
Thanks.
A $G$-grading (or: $G$-gradation) in a graded object (a $G$-graded, $k$-algebra $R$ or a $G$-graded, left $R$-module, $_{R}M$ with $k$ a field or a commutative ring) is usually defined with respect to a group $G$ and it can be shown that for any group $G$, a $G$-grading is the same thing as a (co)action of $(kG)^{*}$ (where $(kG)^{*}$ is the dual hopf algebra of the group hopf algebra $kG$) on the respective object.
A consequence of the above, is that if $G$ is a finite abelian group, in which case $kG\cong (kG)^{*}$ as hopf algebras (i.e. self-dual), then each $G$-grading is equivalent to a specific action of $G$ on the respecting object. $\mathbb{N}$ is not a group and I guess this is why it is custom to speak about a $\mathbb{Z}$-graded object but not an $\mathbb{N}$-graded object.
More generally, gradations can also be defined with respect to some monoid or semi-group, which means that it is legitimate to view your polynomial ring either as $\mathbb{Z}$-graded or $\mathbb{N}$-graded. So, the graded version of Nakayama's Lemma applies. However, in the literature it is the group-grading case which is mostly explored and which presents a wealth of behaviours (in the sense that it can provide deep insights into the structure of the graded ring, algebra or module).