P and Q start running in opposite directions (towards each other) on a circular track starting at diametrically opposite points. They first meet after P has run for 75m and then they next meet after Q has run 100 m after their first meeting. Assume that both of them are running a constant speed. The length of the track (in metre) is:
a)70 b)175 3)250 4)350
my solution
let p and q be speed of P and Q respectively and 2d be circumference since both start at diametrically opposite points so they meet at same time that is
75/p = (d-75)/q .....1
and Q has run 100m after first meeting so P will run 2d - 100 for next meeting
hence 100/q = (2d-100)/p ......2
solving 1 and 2 d is 125m , so 2d = 250m
is my solution correct or wrong ? while answer is 350 here is the link http://www.lofoya.com/Aptitude-Questions-And-Answers/Time-Speed-and-Distance/l1p6.htm check question 27 with solution
Dividing these into two separate runs on a straight track: When the distance between them is $d$, then $P$ has to run $75$ meters before they meet.
When the distance between them is $2d$ then naturally, $P$ has to run twice as far before they meet, so he runs $150$ meters. $Q$ runs $100$ meters, and their sum is the total circumference $250$.
The solution in the link is for some reason assuming that the two are running at the same speed, rather than separate, constant speeds, but I still don't quite follow the argument they make.