Is the following statement:
$\dfrac{1}{1+O(T)} = 1+ {O(T)}$
true, and if so, why?
$$\frac{1}{1+x}=1+O(x),$$
therefore $$\frac{1}{1+O(x)}=1+O(x).$$
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$$\frac{1}{1+x}=1+O(x),$$
therefore $$\frac{1}{1+O(x)}=1+O(x).$$