I'm looking for examples of completely integrable systems and specifically geodesic flows. We remember that when we have a symplectic manifold $(M,\omega)$ (with $M$ of dimension $2n$) and $H:M\rightarrow\mathbb{R}$ a smooth function, its symplectic gradient is the unique field $X_H$ over $M$ satisfying
$$\textrm{d}H=\omega(X_H,\cdot)$$
and we say that the system $(M,\omega,H)$ is completely integrable is there exists $f_1,\ldots,f_{n-1}:M\rightarrow\mathbb{R}$ smooth functions Poisson commuting: $\{f_i,f_j\}=\{f_k,H\}=0$, where $\{f,g\}=\omega(X_f,X_g)$, and with $\textrm{d}f_1,\ldots,\textrm{d}f_{n-1},\textrm{d}H$ linearly independent in a dense set of $M$.
In the cotangent bundle $T^*M$ of a manifold $M$, there exists a canonical symplectic form,
$$\omega_\textrm{can}=\sum{\textrm{d}x_i}\wedge\textrm{d}\xi_i$$
$(x_1,\ldots,x_n,\xi_1,\ldots,\xi_n)$ local coordinates of $T^\star M$. Then, if we consider a riemannian manifold $(M,g)$, we can canonically define a symplectic form on $TM$ with the bundle isomorphism $\Phi:TM\rightarrow T^\star M$ given by
$$\Phi(p,v)=(p,v^\star)$$
where $v^*(w)=g(v,w)$ is the Riesz representation of a functional. Hence we can define $\omega=\Phi^{\star}\omega_\textrm{can}$. In this way, the geodesic flow can be viewed as the flow of the symplectic gradient of the metric hamiltonian $H(p,v)=\frac{1}{2}g_p(v,v)$. Then my question is if the geodesic flow on the tangent bundle of the hyperbolic plane is completely integrable and, if yes, what is the another function beside the metric hamiltonian $H$. Any help will be appreciated.
A complete system of independent and Poisson-commuting first integrals is given by: $$H_1=\frac{x'^2+y'^2}{y^2},$$ $$H_2=\frac{x'}{y^2}.$$ Obviously $H_1$ is the kinetical energy.
Instead the constant of motion $H_2$ is geometrically interpreted by means of the following fact:
You could find interesting this set of notes. It shows two examples of completely integrable geodesic flows: the one on the hyperbolic plane and the other on the revolution surfaces; it appears to me to be enough detailed.