Let $X$ be a compact subset of the complex plane. Is it true that $K_1(C(X)) = K^1(X)$ is a free abelian group? My only basis for thinking this is that it is true for a finite wedge of circles.
2026-03-25 19:09:53.1774465793
Is the $K_1$-group of a compact subset of the plane free?
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