is the language above the {a,b,c} alphabet composed of words of length divisible by 4 starting and ending with the same letter context-free?
I tried doing it with Pumping lemma but im not sure if i did it right.
So f.e i choosed word
z = abacbcaa
k = 2^3 = 8
Then i split z into z = uvwxy, f.e z = a | b | ac | bc | aa
- vw != ϵ
true - |vwx| <= k
true
Now i choose i = 2 so z would be
z = uv^2wx^2y = abbacbcbcaa
It turnded out that the lenght of this words i 11, so it's not Contex-Free? Did I do this right?