Is the length of each interval in the Cantor set itself a member of the Cantor set?

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Considering the Cantor set, which can be covered with a sequence of intervals defined as the following:

$$\{[a_{di}, b_{di}], d=1, 2, ..., \infty, i=1, 2, ..., n_d\}$$

where $d$ indexes the "depth" of each interval within the set, $i$ indexes the various intervals at depth $d$, and $n_d = 2^d$ represents the number of intervals present at depth $d$; that is, $[a_{11}, b_{11}] := [0, \frac{1}{3}], [a_{12}, b_{12}] := [\frac{2}{3}, 1]$, and so on, I am wondering the following:

Is every difference $(b_{di} - a_{di})$, that is the length of interval $i$ at depth $d$, also a member of the Cantor set? This is definitely true for the first few intervals, but I'm not sure how to verify if it's true for all of the intervals.

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Every interval at depth $d$ has the same length - namely, $3^{-i}$. So you're just asking whether $3^{-i}$ is always an element of the Cantor set. And indeed it is - namely, it's the right endpoint of the leftmost interval at depth $i$.