True/False:
If $A$ is a $m×r$ matrix with $r$ independent columns and $B$ is a $r ×n$ matrix with $r$ independent rows, then $AB$ is invertible.
I reasoned like this: Since the resultant matrix is not square, $AB$ is not invertible. Is there a better way to prove this?
You are correct if $n\ne m$.
If $n=m$, then:
If $r<n$ then it can be shown that $AB$ will have a rank of $r$ (can you show this?). Since $r<n$, $AB$ is not invertible in that case.
If $r=n$ then $AB$ is invertible.
The case $r>n$ is impossible (why?).